2=-6k^2-9k

Solution for 2=-6k^2-9k equation:

2=-6k^2-9k

We move all terms to the left:

2-(-6k^2-9k)=0

We get rid of parentheses

6k^2+9k+2=0

a = 6; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·6·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{33}}{2*6}=\frac{-9-\sqrt{33}}{12}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{33}}{2*6}=\frac{-9+\sqrt{33}}{12}
$